A coil in a magnetic field encloses a flux of 0.196 T·m² when the angle between the normal to the coil and the direction of the magnetic field is 42.0°.What flux would go through the coil if the angle were changed to 29.0°? A) 0.167 T·m² B) 0.135 T·m² C) 0.27 T·m² D) 0.231 T·m² E) 0.142 T·m²

Question

Quizplus · Accepted Answer

The flux through a coil is given by the equation: 
Φ = B * A * cosθ
Where B is the magnetic field, A is the area of the coil and θ is the angle between the normal to the coil and the direction of the magnetic field.
Given that Φ1 = 0.196 T·mS-1 and θ1 = 42.0°
Therefore, Φ1 = B * A * cosθ1
0.196 T·mS-1 = B * A * cos42.0°
Similarly, when the angle is changed to 29.0°, the new flux (Φ2) can be calculated as:
Φ2 = B * A * cos29.0°
Thus, Φ2 = Φ1 * cos29.0°/cos42.0°
Φ2 = 0.196 T·mS-1 * cos29.0°/cos42.0°
Φ2 = 0.231 T·mS-1
Therefore, the flux through the coil when the angle is changed to 29.0° is 0.231 T·mS-1, which corresponds to option D.

A Coil in a Magnetic Field Encloses a Flux of 0.196