The current in a coil with a self-inductance of 2.3 mH increases from 0 to 1.9 A in a tenth of a second.What is the induced emf in the coil?
A) 44 mV
B) 4.4 mV
C) 830 mV
D) 0.012 V
E) 87 mV

Question

The current in a coil with a self-inductance of 2.3 mH increases from 0 to 1.9 A in a tenth of a second.What is the induced emf in the coil?
A) 44 mV
B) 4.4 mV
C) 830 mV
D) 0.012 V
E) ​87 mV

Quizplus · Accepted Answer

The induced emf (ε) can be calculated using the formula ε = -L * (ΔI/Δt), where L is the inductance (2.3 mH = 0.0023 H), ΔI is the change in current (1.9 A), and Δt is the change in time (0.1 s). Substituting these values gives ε = -0.0023 * (1.9/0.1) = -0.0437 V = -43.7 mV, which rounds to 44 mV.

The Current in a Coil with a Self-Inductance of 2