An RL series circuit has the following components: 4.8-mH coil,1.6-Ω resistor,13-V battery,ammeter and switch.What is the time constant of this circuit?
A) 3.3E+2 s
B) 3.0E-3 s
C) 1.7E-3 s
D) 5.9E-4 s
E) 3.9E-2 s

Question

An RL series circuit has the following components: 4.8-mH coil,1.6-Ω resistor,13-V battery,ammeter and switch.What is the time constant of this circuit?
A) 3.3E+2 s
B) 3.0E-3 s
C) 1.7E-3 s
D) 5.9E-4 s
E) ​3.9E-2 s

Quizplus · Accepted Answer

The time constant (τ) for an RL circuit is given by τ = L/R, where L is the inductance and R is the resistance. Here, L = 4.8 mH = 4.8 x 10^-3 H and R = 1.6 Ω. So, τ = (4.8 x 10^-3) / 1.6 = 3.0 x 10^-3 s.

An RL Series Circuit Has the Following Components: 4