An emf of 0.52 V is induced in a 0.62-H inductor.What is the rate of change of current through the inductor?
A) 0.84 A/s
B) 1.2 A/s
C) 0.32 A/s
D) 1.14 A/s
E) 0.62 A/s

Question

An emf of 0.52 V is induced in a 0.62-H inductor.What is the rate of change of current through the inductor?
A) 0.84 A/s
B) 1.2 A/s
C) 0.32 A/s
D) 1.14 A/s
E) ​0.62 A/s

Quizplus · Accepted Answer

The rate of change of current (di/dt) through an inductor is given by the formula emf = L * (di/dt). Rearranging gives di/dt = emf / L. Substituting the given values, di/dt = 0.52 V / 0.62 H = 0.84 A/s.

An Emf of 0