A coil in a magnetic field encloses a flux of 0.256 T·m² when the angle between the normal to the coil and the direction of the magnetic field is 70.0°.What flux would go through the coil if the angle were changed to 30.0°? A) 0.648 T·m² B) 0.573 T·m² C) 0.114 T·m² D) 0.198 T·m²

Question

Quizplus · Accepted Answer

We can use the formula for flux through a coil in a magnetic field: Φ = B*A*cos(θ) where Φ is the flux, B is the magnetic field, A is the area enclosed by the coil, and θ is the angle between the normal to the coil and the direction of the magnetic field. We can rearrange the formula to solve for the new flux when the angle is changed to 30.0°: Φ' = B*A*cos(30.0°) = (0.256 T) * (m^2) * cos(30.0°) = 0.648 T·m² Therefore, the answer is A.

A Coil in a Magnetic Field Encloses a Flux of 0.256