A square coil,enclosing an area with sides 3.0 cm long,is wrapped with 2500 turns of wire.A uniform magnetic field perpendicular to its plane is turned on and increases to 0.12 T during an interval of 1.0 s.What average voltage is induced in the coil?
A) 2.5 V
B) 0.27 V
C) 1.2 V
D) 0.12 V

Question

Quizplus · Accepted Answer

The average induced voltage (emf) can be calculated using Faraday's law of electromagnetic induction: emf = -N * (ΔΦ/Δt), where N is the number of turns, ΔΦ is the change in magnetic flux, and Δt is the time interval. The area A of the coil is (0.03 m)^2 = 0.0009 m². The change in magnetic flux ΔΦ = B * A = 0.12 T * 0.0009 m² = 0.000108 Wb. Therefore, emf = -2500 * (0.000108 Wb / 1 s) = 0.27 V.

A Square Coil,enclosing an Area with Sides 3