An inductor has 1000 turns/m and an internal volume of 30 cm³.What is its inductance? A) 0.38 H B) 38 μH C) 3.8 μH D) Insufficient information is given.

Question

Quizplus · Accepted Answer

The inductance of an inductor is given by the formula L = (N^2 * μ * A) / l, where N is the number of turns, μ is the permeability of the core material, A is the cross-sectional area and l is the length of the core. Since the internal volume of the inductor is given and assuming it's cylindrical, we can calculate its length as L = V / A = 30 / (π * (0.5^2)) = 190.98 cm. Now, we can use the given information to calculate the inductance as L = (N^2 * μ * A) / l = (1000^2 * π * 4π * 10^-7 * (0.5^2)) / 190.98 = 38 μH. Therefore, the answer is (B) 38 μH.

An Inductor Has 1000 Turns/m and an Internal Volume of 30