Light in air enters a diamond (n = 2.42)at an angle of incidence of 57.0°.What is the angle of refraction inside the diamond?
A) 20.3°
B) 8.23°
C) 0.354°
D) 10.4°
E) 57.0°

Question

Light in air enters a diamond (n = 2.42)at an angle of incidence of 57.0°.What is the angle of refraction inside the diamond?
A) 20.3°
B) 8.23°
C) 0.354°
D) 10.4°
E) ​57.0°

Quizplus · Accepted Answer

Snell's law: n1 sin θ1 = n2 sin θ2n1 = 1 (air)n2 = 2.42 (diamond)θ1 = 57.0°θ2 = sin^-1((n1/n2) * sin θ1) = sin^-1((1/2.42) * sin 57.0°) = 20.3°

Light in Air Enters a Diamond (N = 2