What is the maximum value of the electric field E at 0.50 m from a 100 W light bulb radiating in all directions? (µ₀ = 4π × 10−⁷ T⋅m/A,c = 3.00 × 10⁸ m/s) A) 3000 V/m B) 155 V/m C) 6000 V/m D) 77 V/m

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Quizplus · Accepted Answer

The intensity I of the light at a distance r from the bulb is given by I = P/(4πr²), where P is the power. The intensity is also related to the electric field E by I = (1/2)ε₀cE². Solving for E gives E = √(2I/ε₀c). Substituting the given values, we find E ≈ 155 V/m.

What Is the Maximum Value of the Electric Field E