A converging lens with two convex surfaces has a front surface with radius of curvature of 14.0 cm;the back surface has radius of curvature of 24.0 cm,and it is made from material with an index of refraction of 2.90.What is the focal length of the lens?

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Quizplus · Accepted Answer

The focal length of a converging lens is given by the lensmaker's equation:1/f = (n-1) * (1/R1 + 1/R2)where n is the index of refraction of the lens material, R1 is the radius of curvature of the front surface, and R2 is the radius of curvature of the back surface.In this case, n = 2.90, R1 = 14.0 cm, and R2 = 24.0 cm. Plugging these values into the lensmaker's equation, we get:1/f = (2.90-1) * (1/14.0 cm + 1/24.0 cm)1/f = 1.90 * (0.0714 cm^-1 + 0.0417 cm^-1)1/f = 0.213 cm^-1f = 4.7 cmTherefore, the focal length of the lens is 4.7 cm.

A Converging Lens with Two Convex Surfaces Has a Front