A certain kind of glass has n_blue = 1.650 for blue light and n_red = 1.610 for red light.If a beam of white light (containing all colors)is incident at an angle of 60.0°,what is the angle between the red and blue light inside the glass? A) 0.45.0° B) 0.22.3° C) 1.81° D) 0.882°

Question

Quizplus · Accepted Answer

First, we can use Snell's law to find the angle of refraction for both red and blue light:

sin(theta red) = (n_air)/(n_red)sin(60°) = (1)/(1.610)sin(60°)
theta red = 30.0°
sin(theta blue) = (n_air)/(n_blue)sin(60°) = (1)/(1.650)sin(60°)
theta blue = 29.4°

Next, we can use the law of refraction to find the angle between the red and blue light inside the glass:

sin(theta red - theta blue) = (n_blue)/(n_red) = (1.650)/(1.610)
theta red - theta blue = sin⁻¹((1.650)/(1.610))
theta red - theta blue = 0.882°

Therefore, the answer is D) 0.882°.

A Certain Kind of Glass Has Nblue = 1

A Certain Kind of Glass Has N_blue = 1