A light source simultaneously emits light of two wavelengths,581 nm and 545 nm,respectively.The source is used in a double-slit interference experiment where the slit spacing is a 0.0441 mm,and the distance between double slits and the screen is 1.70 m.What is the separation between the second-order bright fringes of the two wavelengths as they appear on the screen? (1 nm = 10−⁹ m) A) 0.14 cm B) 0.07 cm C) 0.28 cm D) 0.73 cm E) 8.68 cm

Question

Quizplus · Accepted Answer

The separation between the second-order bright fringes can be calculated using the formula for fringe separation in a double-slit experiment: Δy = (m * λ * L) / d. For the second-order (m=2) bright fringes, calculate Δy for each wavelength and find the difference. For 581 nm: Δy₁ = (2 * 581 * 10⁻⁹ m * 1.70 m) / 0.0441 * 10⁻³ m = 0.0448 m. For 545 nm: Δy₂ = (2 * 545 * 10⁻⁹ m * 1.70 m) / 0.0441 * 10⁻³ m = 0.0420 m. The separation is Δy₁ - Δy₂ = 0.0028 m = 0.28 cm.

A Light Source Simultaneously Emits Light of Two Wavelengths,581 Nm