Helium-neon laser light (λ = 632.8 nm)is sent through a single slit of width 0.56 mm.What is the width of the central maximum on a screen 1.5 m in back of the slit? (1 nm = 10−⁹ m)

Question

Quizplus · Accepted Answer

The width of the central maximum is given by the formula: $ W = \frac{2 \lambda L}{a} $, where $ \lambda $ is the wavelength, $ L $ is the distance to the screen, and $ a $ is the slit width. Substituting the given values: $ W = \frac{2 \times 632.8 \times 10^{-9} \times 1.5}{0.56 \times 10^{-3}} \approx 3.4 $ mm.

Helium-Neon Laser Light (λ = 632