A wavelength of 573 nm yields a first order (m = 1)maximum at 40° with a grating.At what angle will the second order (m = 2)maximum appear for this wavelength?
A) 17.5°
B) No second order maximum exists in this case.
C) -40°
D) 80°

Question

Quizplus · Accepted Answer

The grating equation is d*sin(θ) = m*λ. For m = 1, θ = 40°, so d*sin(40°) = 573 nm. For m = 2, d*sin(θ) = 2*573 nm. Since sin(θ) cannot exceed 1, no angle θ satisfies this for m = 2, so no second order maximum exists.

A Wavelength of 573 Nm Yields a First Order (M