The pupil of a cat's eye narrows to a slit of width 0.5 mm in daylight.Assuming a wavelength of 500 nm,what is the angular resolution? (1 nm = 10−⁹ m) A)1 × 10−³ rad B)5 × 10−³ rad C)1 × 10−⁴ rad D)5 × 10−⁴ rad E)2.5 × 10−⁴ rad

Question

Quizplus · Accepted Answer

The angular resolution can be calculated using the formula θ = λ / D, where λ is the wavelength of light and D is the diameter of the aperture (in this case, the width of the pupil). Substituting λ = 500 nm (500 × 10^-9 m) and D = 0.5 mm (0.5 × 10^-3 m) into the formula gives θ = (500 × 10^-9 m) / (0.5 × 10^-3 m) = 1 × 10^-6 m/m = 1 × 10^-6 rad = 1 × 10^-6 rad, which simplifies to 1 × 10^-6 rad, matching choice A.

The Pupil of a Cat's Eye Narrows to a Slit