A proton with mass 1.67 × 10−²⁷ kg moves in an accelerator with speed of 0.900c.What is its kinetic energy? (c = 3.00 × 10⁸ m/s) A) 1.95 × 10−¹⁰ J B) 1.00 × 10−¹⁰ J C) 3.70 × 10−¹⁰ J D) 1.35 × 10−¹⁰ J

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The correct answer is A because the kinetic energy of the proton is given by the equation:$$K = (1/2)mv^2$$where:* K is the kinetic energy in joules (J)* m is the mass of the proton in kilograms (kg)* v is the speed of the proton in meters per second (m/s)Plugging in the given values, we get:$$K = (1/2)(1.67 × 10^{-27} kg)(0.900c)^2$$$$K = (1/2)(1.67 × 10^{-27} kg)(0.900 × 3.00 × 10^8 m/s)^2$$$$K = 1.95 × 10^{-10} J$$

A Proton with Mass 1