What is the highest frequency of the photons produced by a 28-kV x-ray machine? (h = 6.63 × 10−³⁴ J⋅s)

Question

Quizplus · Accepted Answer

The highest frequency of photons produced by a 28-kV x-ray machine can be calculated using the formula f = E/h, where E is the energy of the photon and h is the Planck's constant. The maximum energy of photons produced by a 28-kV x-ray machine is given by E = 28,000 eV. Converting this to joules, we get E = 4.48 × 10^-15 J. Substituting this value and the value of Planck's constant (h = 6.63 × 10^-34 J⋅s) in the formula, we get f = (4.48 × 10^-15)/(6.63 × 10^-34) = 6.8 × 10^18 Hz. Therefore, the highest frequency of photons produced by a 28-kV x-ray machine is 6.8 × 10^18 Hz, which corresponds to answer choice D.

What Is the Highest Frequency of the Photons Produced by a 28-KV