A quantum of radiation has an energy of 1.3 keV.What is its frequency? (h = 6.63 × 10−³⁴ J⋅s and 1 eV = 1.60 × 10−¹⁹ J) A) 6.3 × 10¹⁷ Hz B) 3.1 × 10¹⁷ Hz C) 4.8 × 10¹⁷ Hz D) 7.2 × 10¹⁷ Hz

Question

Quizplus · Accepted Answer

The energy of a photon is given by E = hf, where h is Planck's constant and f is the frequency of the radiation.

We are given the energy of the photon as 1.3 keV, which we need to convert to Joules: 
1.3 keV × (1.60 × 10^-19 J/eV) = 2.08 × 10^-16 J

Now we can use the equation E = hf to solve for f: 
2.08 × 10^-16 J = (6.63 × 10^-34 J·s) f 
f = (2.08 × 10^-16 J) / (6.63 × 10^-34 J·s) 
f = 3.1 × 10^17 Hz

Therefore, the answer is B) 3.1 × 10^17 Hz.

A Quantum of Radiation Has an Energy of 1