A light-emitting diode has a power output of 0.3 W.If 590 nm is the average wavelength of the source,about how many photons are emitted per second? (h = 6.63 × 10−³⁴ J⋅s,c = 3.00 × 10⁸ m/s,and 1 nm = 10−⁹ m) A)10²¹ B)10²⁵ C)10¹⁸ D)10²⁹

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First, calculate the energy of a single photon using the formula $E = \frac{hc}{\lambda}$, where $h = 6.63 \times 10^{-34} \, \text{J} \cdot \text{s}$, $c = 3.00 \times 10^{8} \, \text{m/s}$, and $\lambda = 590 \times 10^{-9} \, \text{m}$. Then, divide the total power output by the energy per photon to find the number of photons emitted per second.

A Light-Emitting Diode Has a Power Output of 0