The red light from a HeNe laboratory laser results from a transition in Ne.Determine the wavelength of the light given off if the energy difference between states is 2.29 eV.(h = 6.63 × 10−³⁴ J⋅s,c = 3.00 × 10⁸ m/s,1 eV = 1.60 × 10−¹⁹ J,and 1 nm = 10−⁹ m) A) 181 nm B) 870 nm C) 544 nm D) 2840 nm E) 428 nm

Question

Quizplus · Accepted Answer

The energy difference between states can be calculated by multiplying the given value with the charge of an electron:
ΔE = 2.29 eV x 1.60 × 10−19 J/eV = 3.664 × 10−19 J
Using the equation E = hc/λ, we can find the wavelength of the light:
λ = hc/ΔE = (6.63 × 10−34 J⋅s x 3.00 × 108 m/s) / 3.664 × 10−19 J = 544 nm
Therefore, the answer is choice C).

The Red Light from a HeNe Laboratory Laser Results from a Transition