If a hydrogen atom,originally in its ground state of energy -13.6 eV,absorbs a photon of energy 22.0 eV,what is the resulting kinetic energy of the electron if the proton has negligible kinetic energy?
A) Such a photon cannot be absorbed in this case.
B) 8.4 eV
C) 2.4 eV
D) 16.0 eV

Question

Quizplus · Accepted Answer

The energy required to ionize the hydrogen atom from the ground state is 13.6 eV. If a photon of 22.0 eV is absorbed, the excess energy after ionization is 22.0 eV - 13.6 eV = 8.4 eV, which becomes the kinetic energy of the electron.

If a Hydrogen Atom,originally in Its Ground State of Energy