The half-life of ¹⁹N is 0.42 s.What is the decay constant for this isotope? A) 1.7 × 10^-11 Ci B) 1.7 s^-1 C) 1.1 s^-1 D) The decay constant is not defined for a half-life of less than one second.

Question

Quizplus · Accepted Answer

The decay constant is given by the formula λ = ln2/T1/2 where T1/2 is the half-life of the isotope. Substituting the given value, we get λ = ln2/0.42 s ≈ 1.7 s^-1. Thus, the correct choice is B.

The Half-Life of 19N Is 0

The Half-Life of ¹⁹N Is 0