A solution of 34.5% sulfuric acid by weight in water has a density of 1.26 g/mL.How many grams of sulfuric acid are needed to make 3.22 L of this solution? A)1.20 × 10⁵ g B)882 g C)135 g D)1.40 × 10³ g E)1.40 × 10⁵ g

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Quizplus · Accepted Answer

To find the grams of sulfuric acid, first calculate the total mass of the solution: 3.22 L × 1.26 g/mL = 4057.2 g. Then, calculate the mass of sulfuric acid: 34.5% of 4057.2 g = 0.345 × 4057.2 g = 1400 g, which is 1.40 × 10³ g.

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