How many atoms of lead are required to cover a 33.0 cm by 45.0 cm area with a sheet of lead that is 0.140 mm thick? The density of lead is 11.35 g/cm³. A)6.86 × 10²³ B)2.29 × 10²⁶ C)2.29 × 10²⁵ D)6.86 × 10²² E)1.42 × 10²⁶

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The Answer of How many atoms of lead are required to cover a 33.0 cm by 45.0 cm area with a sheet of lead that is 0.140 mm thick? The density of lead is 11.35 g/cm³. A)6.86 × 10²³ B)2.29 × 10²⁶ C)2.29 × 10²⁵ D)6.86 × 10²² E)1.42 × 10²⁶

How Many Atoms of Lead Are Required to Cover a 33.0