Elemental analysis of 50.0000 g of a compound showed that it contained 12.7520 g C,3.2105 g H,and the rest was S.The empirical formula of this compound is ________.

Question

Quizplus · Accepted Answer

To find the empirical formula, we need to convert the masses of each element to moles using their respective atomic masses. 
- C: 12.7520 g / 12.011 g/mol = 1.06206 mol 
- H: 3.2105 g / 1.008 g/mol = 3.18513 mol 
- S: (50.0000 g - 12.7520 g - 3.2105 g) / 32.066 g/mol = 1.16173 mol

Next, we need to find the smallest whole number ratio of these elements. Dividing each value by the smallest value (1.06206 mol) gives: 
- C: 1.0000 
- H: 2.9995 (which we'll round to 3) 
- S: 1.0947 (which we'll round to 1)

Thus, the empirical formula is CH3S. The only answer choice that has CH3S as its empirical formula is C.

Elemental Analysis of 50