What is the oxidation number of the chromium atom in K₂CrO₄?

Question

Quizplus · Accepted Answer

The oxidation state of oxygen is typically -2, and there are two oxygen atoms in the formula. Potassium has an oxidation state of +1, sulfur has an oxidation state of -2, and there is only one chromium atom in the formula. Therefore, using the sum of the oxidation states of all atoms in the formula, we get:

(2 x -2) + 1 + (-2) + x + (-2) + 4 + (-2) = 0

Simplifying:

-4 + 1 - 2 + x - 2 - 2 = 0

x - 9 = 0

x = +9

Therefore, the oxidation state of chromium in the compound is +6.

What Is the Oxidation Number of the Chromium Atom in K2CrO4

What Is the Oxidation Number of the Chromium Atom in K₂CrO₄