What volume of 6.0 M sulfuric acid is required for the preparation of 500.0 mL of 0.30 M solution?

Question

Quizplus · Accepted Answer

To find the volume of the concentrated solution needed, use the dilution formula: $C_1V_1 = C_2V_2$, where $C_1$ and $V_1$ are the concentration and volume of the concentrated solution, and $C_2$ and $V_2$ are the concentration and volume of the diluted solution. Plugging in the given values: $6.0\, \text{M} \times V_1 = 0.30\, \text{M} \times 500.0\, \text{mL}$. Solving for $V_1$ gives $V_1 = \frac{0.30\, \text{M} \times 500.0\, \text{mL}}{6.0\, \text{M}} = 25\, \text{mL}$.

What Volume of 6