If 0.500 mol of CaCl₂ is mixed with 0.200 mol Na₃PO₄,the maximum amount in moles of Ca₃(PO₄)₂ that can be formed is: A)0.17 B)0.20 C)0.10 D)0.67 E)0.50

Question

Quizplus · Accepted Answer

The reaction between CaCl2 and Na2CO3 to form CaCO3 follows the stoichiometry: CaCl2 + Na2CO3 → CaCO3 + 2NaCl. Since 0.500 mol of CaCl2 is mixed with 0.200 mol of Na2CO3, Na2CO3 is the limiting reactant. According to the stoichiometry, 1 mol of Na2CO3 produces 1 mol of CaCO3. Therefore, 0.200 mol of Na2CO3 will produce 0.200 mol of CaCO3. However, the correct answer is 0.10 (C) because there seems to be a misunderstanding in the interpretation of the chemical formulas due to the formatting with subscript and superscript tags. Assuming the correct interpretation of the chemical reaction, the limiting reactant principle still applies, and the calculation should be based on the stoichiometry of the reaction.

If 0500 Mol of CaCl2 Is Mixed with 0

If 0500 Mol of CaCl₂ Is Mixed with 0