Chromium in its +VI oxidation state is considered a hazardous,carcinogenic species,destruction of which may be accomplished by the process symbolized as: 4 Zn + K₂Cr₂O₇ + 7 H₂SO₄ → 4 ZnSO₄ + 2 CrSO₄ + K₂SO₄ + 7 H₂O If 1.0 mol of each reactant is mixed,what is the limiting reagent,and what is the theoretical yield in moles of chromium(II)sulfate? A)limiting reagent Zn,0.50 mol chromium(II)sulfate B)limiting reagent K₂Cr2O₇,2.0 mol chromium(II)sulfate C)limiting reagent H₂SO₄,0.29 mol chromium(II)sulfate D)limiting reagent H₂,1.0 mol chromium(II)sulfate E)no limiting reagent,1.0 mol chromium(II)sulfate

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The limiting reagent is sulfuric acid (H₂SO₄) because based on the stoichiometry of the reaction, 7 moles of H₂SO₄ are required to react with 1 mole of K₂Cr₂O₇ and 4 moles of Zn, but only 1 mole of each reactant is provided. Therefore, H₂SO₄ will be consumed first. The theoretical yield of chromium(II) sulfate can be calculated based on the stoichiometry of the reaction, which shows that 1 mole of K₂Cr₂O₇ produces 2 moles of CrSO₄. However, since H₂SO₄ is the limiting reagent and only enough to partially react, the actual yield is lower. Given the ratio of H₂SO₄ to K₂Cr₂O₇ in the reaction (7:1), and only 1 mole of H₂SO₄ is available, it will only allow for a fraction (1/7) of the reaction to proceed, leading to a theoretical yield of 0.29 moles of chromium(II) sulfate.

Chromium in Its +VI Oxidation State Is Considered a Hazardous,carcinogenic