How many grams of calcium chloride are needed to produce 1.50 g of potassium chloride?
CaCl₂(aq) + K₂CO₃(aq) → 2 KCl(aq) + CaCO₃(aq)

Question

How many grams of calcium chloride are needed to produce 1.50 g of potassium chloride? CaCl₂(aq)+ K₂CO₃(aq)→ 2 KCl(aq)+ CaCO₃(aq)

Quizplus · Accepted Answer

The balanced chemical equation is CaCl2(aq) + K2CO3(aq) → 2 KCl(aq) + CaCO3(aq). To find the grams of CaCl2 needed to produce 1.50 g of KCl, we use stoichiometry. The molar mass of KCl is approximately 74.55 g/mol, so 1.50 g of KCl is 1.50 g / 74.55 g/mol = 0.0201 mol. Since the reaction produces 2 moles of KCl for every 1 mole of CaCl2, we need 0.0201 mol / 2 = 0.01005 mol of CaCl2. The molar mass of CaCl2 is approximately 110.98 g/mol, so the mass of CaCl2 needed is 0.01005 mol * 110.98 g/mol = 1.12 g.

How Many Grams of Calcium Chloride Are Needed to Produce