When 7.00 × 10²² molecules of ammonia react with 6.00 × 10²² molecules of oxygen according to the chemical equation shown below,how many grams of nitrogen gas are produced?
4 NH₃(g) + 3 O₂(g) → 2 N₂(g) + 6 H₂O(g)

Question

Quizplus · Accepted Answer

4 moles of ammonia react with 3 moles of oxygen to produce 2 moles of nitrogen gas. Therefore, 7.00 × 10²² molecules of ammonia will react with 6.00 × 10²² molecules of oxygen to produce 3.50 × 10²² molecules of nitrogen gas. The molar mass of nitrogen gas is 28.01 g/mol. Therefore, the mass of nitrogen gas produced is 3.50 × 10²² molecules × (28.01 g/mol) / (6.022 × 10²³ molecules/mol) = 1.63 g.

When 700 × 1022 Molecules of Ammonia React with 6

When 700 × 10²² Molecules of Ammonia React with 6