How many millilitres of a 9.0 mol L^-1 H₂SO₄(aq)solution are needed to make 0.35 L of a 3.5 mol L^-1 solution?

Question

Quizplus · Accepted Answer

Use the following equation to solve the problem:

Molarity x Volume (in liters) = moles of solute

Let's first find the moles of solute in the desired 0.35 L solution:

moles = Molarity x Volume
moles = 3.5 mol/L x 0.35 L
moles = 1.225 mol

Now we need to use the same equation to find the volume of the 9.0 mol/L solution that contains 1.225 mol of solute:

Volume (in liters) = moles of solute / Molarity
Volume = 1.225 mol / 9.0 mol/L
Volume = 0.1361 L

Finally, we need to convert this volume to milliliters:

Volume = 0.1361 L x 1000 mL/L
Volume = 136.1 mL

Therefore, we need 140 mL (rounded to 3 significant figures) of the 9.0 mol/L solution to make 0.35 L of a 3.5 mol/L solution. The answer is C.

How Many Millilitres of a 9