How many millilitres of 0.200 mol L^-1 FeCl₃(aq) are needed to react with an excess of Na₂S(aq) to produce 1.38 g of Fe₂S₃ if the percent yield for the reaction is 65.0%?
3 Na₂S(aq) + 2 FeCl₃(aq) → Fe₂S₃(s) + 6 NaCl(aq)

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The Answer of How many millilitres of 0.200 mol L^-1 FeCl₃(aq)are needed to react with an excess of Na₂S(aq)to produce 1.38 g of Fe₂S₃ if the percent yield for the reaction is 65.0%? 3 Na₂S(aq)+ 2 FeCl₃(aq)→ Fe₂S₃(s)+ 6 NaCl(aq)

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