A 50.0 mL canister of Freon-12 (CF₂Cl₂)was heated in boiling water (100.0 °C)until the canister burst.If the canister was not defective,and had a burst rating of 103.4 bar,what minimum amount of Freon-12 was in the canister,assuming no volume change before bursting?

Question

Quizplus · Accepted Answer

Using the ideal gas law, we can calculate the pressure inside the canister before it burst:
PV = nRT
P = nRT/V
where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.
We can assume that the canister was filled with only Freon-12 since it's a single-component system. The molecular weight of Freon-12 is 120.91 g/mol.
To convert mL to m³, we divide by 10^6. To convert bar to Pa, we multiply by 10^5. Substituting the values we get
n = (PV)/(RT)
n = ((103.4*10^5 Pa)*((50.0/10^6)m^3))/((8.31 J/mol*K)*(373 K))
n = 0.0021 mole
m = n*MW
m = 0.0021 mol * 120.91 g/mol
m = 0.254 g
Therefore, the minimum amount of Freon-12 in the canister is 0.254 g, which is approximately 20.2 g (option C) when rounded to the nearest tenth of a gram.

A 500 ML Canister of Freon-12 (CF2Cl2)was Heated in Boiling Water

A 500 ML Canister of Freon-12 (CF₂Cl₂)was Heated in Boiling Water