Diethyl ether (CH₃CH₂OCH₂CH₃)was the first general anesthetic.It was first used in 1846 for surgical procedures.What is the density in g/L of diethyl ether at 27 °C and 1.11 atm? A)37.1 g/L B)2.03 × 10³g/L C)2.71 g/L D)3.34 g/L E)0.299 g/L

Question

Quizplus · Accepted Answer

We can use the ideal gas law equation: PV=nRT, where P=1.11 atm, T=27+273=300K, R=0.08206 L atm/mol K, and n=1 mole of diethyl ether. We need to solve for V and then divide by the mass of 1 mole of diethyl ether (74.12 g/mol) to get the density in g/L.

Rearranging the equation, we get V=nRT/P. Substituting the values, we get V=(1 mol)(0.08206 L atm/mol K)(300 K)/(1.11 atm)=20.94 L.

Dividing by the mass of 1 mole of diethyl ether, we get the density in g/L: 74.12 g/20.94 L = 3.54 g/L, which is closest to answer choice D, 3.34 g/L.

Diethyl Ether (CH3CH2OCH2CH3)was the First General Anesthetic

Diethyl Ether (CH₃CH₂OCH₂CH₃)was the First General Anesthetic