14.0 g of metal at 24.0 °C has 250 joules of heat added to it.The metal's specific heat is 0.105 J/g °C.What is its final temperature?

Question

Quizplus · Accepted Answer

First, we need to use the formula for heat (q) to calculate the change in temperature (ΔT) of the metal:

q = (m)(c)(ΔT)

where q = 250 J, m = 14.0 g, and c = 0.105 J/g °C.

Solving for ΔT, we get:

ΔT = q / (m)(c)
ΔT = 250 J / (14.0 g)(0.105 J/g °C)
ΔT ≈ 163.3 °C

Finally, we can use this value to determine the metal's final temperature:

Final temperature = Initial temperature + ΔT
Final temperature = 24.0 °C + 163.3 °C
Final temperature ≈ 187.3 °C

Therefore, the correct answer is C: [250 /(14.0)(0.105)] + 24.0 °C.

140 G of Metal at 24