1219 joules of heat raise the temperature of 250 g of metal by 64 °C.What is the specific heat of the metal in J/(g °C?)
A) (1219) (250) (64) J/(g °C)
B) (64) (250/1219) J/(g °C)
C) (1219) (64/250) J/(g °C)
D) (1219) (250/64) J/(g °C)
E) (1219) /(250 × 64) J/(g °C)
Correct Answer:
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