Given the bond enthalpies N-H (389) ,Cl-Cl (243) ,N-Cl (201) ,and H-Cl (431) in kJ/mol,compute ΔH° in kJ/mol for:
NH3(g) + Cl2(g) → NH2Cl + HCl(g) .
A) -393 kJ/mol
B) -1100 kJ/mol
C) +71 kJ/mol
D) +393 kJ/mol
E) 0 kJ/mol
Correct Answer:
Verified
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