Ethyl alcohol (CH₃CH₂OH)has a heat of fusion of 5.01 kJ/mol.How much heat in kJ is required to melt 137 g of ethyl alcohol? A)1.70 × 10^{3 kJ} B)129 ^kJ C)686 ^kJ D)5.01 ^kJ E)14.9 ^kJ

Question

Quizplus · Accepted Answer

To find the heat required to melt 137 g of ethyl alcohol, we first need to calculate the number of moles of ethyl alcohol. The molar mass of ethyl alcohol (C2H5OH) is approximately 46 g/mol. Therefore, 137 g of ethyl alcohol is equivalent to $137 \, \text{g} \div 46 \, \text{g/mol} = 2.98 \, \text{mol}$. Since the heat of fusion is 5.01 kJ/mol, the total heat required is $2.98 \, \text{mol} \times 5.01 \, \text{kJ/mol} = 14.9 \, \text{kJ}$.

Ethyl Alcohol (CH3CH2OH)has a Heat of Fusion of 5

Ethyl Alcohol (CH₃CH₂OH)has a Heat of Fusion of 5