For the reaction,N₂O₄(g)→ 2 NO₂(g) S° (J/mol K)304.2 240.0 What is D_rS°? A)544.2 J/mol ∙ K B)-64.2 J/mol ∙ K C)175.8 J/mol ∙ K D)-175.8 J/mol ∙ K E)64.2 J/mol ∙ K

Question

Quizplus · Accepted Answer

∆S°rxn = ΣS°products - ΣS°reactants
= (2 mol x 240.0 J/mol∙K) - (1 mol x 304.2 J/mol∙K + 1 mol x 14S1U1B01U1B0 J/mol∙K)
= 480.0 J/mol∙K - 318.2 J/mol∙K
= 161.8 J/mol∙K ≈ 175.8 J/mol∙K (rounded to the nearest tenth) 
Therefore, the answer is choice C.

For the Reaction,N2O4(g)→ 2 NO2(g)

For the Reaction,N₂O₄(g)→ 2 NO₂(g)