For a reaction K_eq = 1.2 × 10^-6 at T = 200 K.What is Δ_rG° for the reaction? A)-22.7 kJ/mol B)53.6 kJ/mol C)22.7 kJ/mol D)-53.6 kJ/mol E)170 kJ/mol

Question

Quizplus · Accepted Answer

Using the equation ΔG° = -RTln(K), where R is the gas constant and T is the temperature in Kelvin, we can find ΔG° for the reaction:

ΔG° = -RTln(K)
ΔG° = -(8.314 J/mol·K)(200 K)ln(1.2 × 10^-6)
ΔG° = 22.7 kJ/mol

Note that we use ln instead of log because the value of K is very small.

Therefore, the correct choice is C.

For a Reaction Keq = 1