Arrange the following three aqueous solutions (all 250 cm³ in volume)according to decreasing osmotic pressure at 273 K: 5 g of C₂H₅OH,5 g C₆H₁₂O₆ ,and 5 g C₁₂H₂₂O_11. A)C₂H₅OH C₆H₁₂O₆ C₁₂H₂₂O₁₁ B)C₂H₅OH C₆H₁₂O₆= C₁₂H₂₂O₁₁ C)C₆H₁₂O₆ C₂H₅OH C₁₂H₂₂O₁₁ D)C₁₂H₂₂O₁₁ C₆H₁₂O₆ C₂H₅OH E)C₁₂H₂₂O₁₁ C₂H₅OH C₆H₁₂O₆

Question

Arrange the following three aqueous solutions (all 250 cm³ in volume)according to decreasing osmotic pressure at 273 K: 5 g of C₂H₅OH,5 g C₆H₁₂O₆ ,and 5 g C₁₂H₂₂O_11. A)C₂H₅OH > C₆H₁₂O₆> C₁₂H₂₂O₁₁ B)C₂H₅OH > C₆H₁₂O₆= C₁₂H₂₂O₁₁ C)C₆H₁₂O₆> C₂H₅OH > C₁₂H₂₂O₁₁ D)C₁₂H₂₂O₁₁> C₆H₁₂O₆> C₂H₅OH E)C₁₂H₂₂O₁₁> C₂H₅OH> C₆H₁₂O₆

Quizplus · Accepted Answer

The osmotic pressure of a solution is directly proportional to the concentration of solute particles in it. Here, all three solutions have the same volume, but the number of solute particles in them will be different, depending on their molar mass. To calculate the number of particles, we need to convert the given masses to moles, and then to particles. The molar mass of C₂H₅OH is 339.65 g/mol. So, Number of particles in 5 g of C₂H₅OH = (5 g / 339.65 g/mol) * 6.022 * 10^23 = 8.87 * 10^21 Similarly, the molar mass of C₆H₁₂O₆ is 532.81 g/mol, and the molar mass of C₁₂H₂₂O₁₁ is 647.87 g/mol. Using these values, we can calculate the number of particles in the other two solutions. Number of particles in 5 g of C₆H₁₂O₆ = 4.45 * 10^21 Number of particles in 5 g of C₁₂H₂₂O₁₁ = 3.64 * 10^21 Thus, the order of osmotic pressure will be: C₂H₅OH > C₆H₁₂O₆ > C₁₂H₂₂O₁₁ Hence, option A is correct.

Arrange the Following Three Aqueous Solutions (All 250 Cm3 in Volume)according

Arrange the Following Three Aqueous Solutions (All 250 Cm³ in Volume)according