252 mL of 3.00 M H₂SO₄(aq)are added to 1.50 L of 0.500 M H₂SO₄(aq).What is the concentration of the resulting solution?

Question

Quizplus · Accepted Answer

To solve this problem, we can use the formula:

M1V1 + M2V2 = M3V3

where M1 and V1 are the concentration and volume of the first solution, M2 and V2 are the concentration and volume of the second solution, and M3 is the concentration of the resulting solution when the two are mixed.

Plugging in the values we have:

M1 = 3.00 M
V1 = 0.252 L
M2 = 0.500 M
V2 = 1.50 L
M3 = ?

M3 = (M1V1 + M2V2) / V3
V3 = V1 + V2 = 0.252 L + 1.50 L = 1.752 L

M3 = (3.00 M)(0.252 L) + (0.500 M)(1.50 L) / 1.752 L = 0.860 M

Therefore, the concentration of the resulting solution is 0.860 M, which is answer choice B.

252 ML of 3