A solution of LiCl in water has x_LiCl = 0.0900.What is the molality? A)4.46 mol kg^-1 LiCl B)5.00 mol kg^-1 LiCl C)5.49 mol kg^-1 LiCl D)9.89 mol kg^-1 LiCl

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Quizplus · Accepted Answer

The molality (m) is calculated using the formula: m = (moles of solute) / (mass of solvent in kg). Given x_LiCl = 0.0900, the moles of LiCl is 0.0900 and moles of water is 0.9100 (since x_water = 1 - x_LiCl). Assuming 1 mole of solution, the mass of water is 0.9100 moles * 18.015 g/mol = 16.384 g = 0.016384 kg. Molality = 0.0900 moles / 0.016384 kg = 5.49 mol/kg.

A Solution of LiCl in Water Has XLiCl = 0

A Solution of LiCl in Water Has X_LiCl = 0