For the reaction: H₂(g)+ I₂(g)⇌ 2 HI(g),K_c = 92.0 When equilibrium concentrations of HI and I₂ are [HI] = 0.115 M and [I₂] = 0.250 M,the equilibrium concentration of [H₂] is:

Question

Quizplus · Accepted Answer

The equilibrium constant expression for the reaction is:K_c = [HI]²/[H₂][I₂]Substituting the given equilibrium concentrations into the expression, we get:92.0 = (0.115 M)²/[H₂](0.250 M)Solving for [H₂], we get:[H₂] = (0.115 M)²/(92.0 * 0.250 M) = 5.75 × 10^-4 MTherefore, the correct choice is B) 5.75 × 10^-4 M.

For the Reaction: H2(g)+ I2(g)⇌ 2 HI(g),Kc = 92

For the Reaction: H₂(g)+ I₂(g)⇌ 2 HI(g),K_c = 92