For the reaction CO(g)+ 3 H₂(g)⇌ H₂O(g)+ CH₄(g),K_c = 190 at 1000 K.If a vessel is filled with these gases such that the initial concentrations are [CO] = 0.025 M,[H₂] = 0.045 M,[H₂O] = 0.025,M and [CH₄] = 0.046 M,in which direction will a reaction occur and why?

Question

Quizplus · Accepted Answer

To determine the direction of the reaction, we calculate the reaction quotient, $Q_c$, and compare it to the equilibrium constant, $K_c$. The reaction is CO(g) + $H_2O(g) \rightleftharpoons H_2O(g) + CH_4(g)$, with $K_c = 190$ at 1000 K. Given concentrations are [CO] = 0.025 M, $[H_2O] = 0.045 M$, $[H_2O] = 0.025 M$, and $[CH_4] = 0.046 M$. The reaction quotient, $Q_c$, is calculated as $\frac{[H_2O][CH_4]}{[CO][H_2O]^3}$. Substituting the given concentrations, $Q_c = \frac{0.025 \times 0.046}{0.025 \times (0.045)^3} = 505$. Since $Q_c > K_c$, the reaction will proceed toward the reactants to reach equilibrium.

For the Reaction CO(g)+ 3 H2(g)⇌ H2O(g)+ CH4(g),Kc = 190

For the Reaction CO(g)+ 3 H₂(g)⇌ H₂O(g)+ CH₄(g),K_c = 190