The solubility product constant of Mg(OH) 2 is 9.0 × 10-12.If an aqueous solution is 0.010 M with respect to Mg2+ ion,the amount of [OH-] required to start the precipitation of Mg(OH) 2(s) is:
A) 1.5 × 10-7 M
B) 3.0 × 10-5 M
C) 3.0 × 10-7 M
D) 9.0 × 10-10 M
E) 1.5 × 10-5 M
Correct Answer:
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