Determine E°_cell for the reaction: 2 Al(aq) + 3 Zn²⁺(aq) → 2 Al³⁺(aq) + 3 Zn(s) .The half reactions are:
Al³⁺(aq) + 3 e^- → Al(s) E° = -1.676 V
Zn²+(aq) + 2 e^- → Zn(s) E° = -0.763 V

Question

Determine E°_cell for the reaction: 2 Al(aq)+ 3 Zn²⁺(aq)→ 2 Al³⁺(aq)+ 3 Zn(s).The half reactions are: Al³⁺(aq)+ 3 e^- → Al(s)E° = -1.676 V Zn²+(aq)+ 2 e^- → Zn(s)E° = -0.763 V

Quizplus · Accepted Answer

E°cell = E°cathode - E°anode. Here, Al is reduced (E° = -1.676 V) and Zn is oxidized (E° = -0.763 V). Thus, E°cell = (-0.763) - (-1.676) = 0.913 V.

Determine E°cell for the Reaction: 2 Al(aq)+ 3 Zn2+(aq)→ 2

Determine E°_cell for the Reaction: 2 Al(aq)+ 3 Zn²⁺(aq)→ 2