Calculate the Ksp of lead iodide from the following standard electrode potentials,at 25 °C:
2 e- + PbI2(S) → Pb(s) + 2 I-(aq) E° = -0.365 V
2 e- + Pb2+(aq) → Pb(s) E° = -0.126 V
A) 8 × 10-9
B) 9 × 10-5
C) 2 × 10-17
D) 5 × 10-13
E) 6 × 10-5
Correct Answer:
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