For the following voltaic cell,determine the [Cl^-] when
= 0.500 atm,[Zn²⁺] = 1.77 × 10^-2 M,and E_cell = 2.250 V.The half-reactions at 25 °C are:
Cl₂(g) + 2 e^- → 2 Cl^-(aq) E° = +1.358 V
Zn²⁺(aq) + 2 e^- → Zn(s) E° = -0.763 V
Zn(s) ∣ Zn²⁺(aq) Cl^-(aq) ,Cl₂(g) ∣ Pt(s)

Question

For the following voltaic cell,determine the [Cl^-] when

For the following voltaic cell,determine the [Cl<sup>-</sup>] when = 0.500 atm,[Zn<sup>2+</sup>] = 1.77 × 10<sup>-2</sup> M,and E<sub>cell</sub> = 2.250 V.The half-reactions at 25 °C are: Cl<sub>2</sub>(g) + 2 e<sup>-</sup> → 2 Cl<sup>-</sup>(aq) E° = +1.358 V Zn<sup>2+</sup>(aq) + 2 e<sup>-</sup> → Zn(s) E° = -0.763 V Zn(s) ∣ Zn<sup>2+</sup>(aq) Cl<sup>-</sup>(aq) ,Cl<sub>2</sub>(g) ∣ Pt(s) A) 5.48 × 10<sup>-6</sup> M B) 2.32 × 10<sup>-3</sup> M C) 0.0296 M D) 0.0939 M E) 0.0352 M

= 0.500 atm,[Zn²⁺] = 1.77 × 10^-2 M,and E_cell = 2.250 V.The half-reactions at 25 °C are:
Cl₂(g) + 2 e^- → 2 Cl^-(aq) E° = +1.358 V
Zn²⁺(aq) + 2 e^- → Zn(s) E° = -0.763 V
Zn(s) ∣ Zn²⁺(aq)

Cl^-(aq) ,Cl₂(g) ∣ Pt(s)

Quizplus · Accepted Answer

The Answer of For the following voltaic cell,determine the [Cl^-] when = 0.500 atm,[Zn²⁺] = 1.77 × 10^-2 M,and E_cell = 2.250 V.The half-reactions at 25 °C are: Cl₂(g)+ 2 e^- → 2 Cl^-(aq)E° = +1.358 V Zn²⁺(aq)+ 2 e^- → Zn(s)E° = -0.763 V Zn(s)∣ Zn²⁺(aq) Cl^-(aq),Cl₂(g)∣ Pt(s)

For the Following Voltaic Cell,determine the [Cl-] When

For the Following Voltaic Cell,determine the [Cl^-] When